$p H=7+\frac{1}{2} P^{k a}-\frac{1}{2} P^{K b}$
$p H=7+\frac{1}{2} \times 4.77-\frac{1}{2} \times 3.27$
$p H=7 \times \frac{1}{2} \times 1.5$
$p H=7.75$
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$SO _{2} Cl _{2}+2 H _{2} O \rightarrow H _{2} SO _{4}+2 HCl$ $16\,moles$ of $NaOH$ is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $SO _{2} Cl _{2}$ used is.
$A : 3\,, 2\,, -2\,, +\, \frac{1}{2}$
$B : 3\,, 0\,, 0\,, + \,\frac{1}{2}$
What is true for $A$ and $B$