MCQ
The pair in which both species have same magnetic moment (spin only value) is
  • A
    $[Cr(H_2O)_6]^{2+} ,\,\,[CoCl_4]^{2-}$
  • $[Cr(H_2O)_6]^{2+} ,\,\,[Fe(H _2O)_6]^{2+}$
  • C
    ${[Mn{({H_2}O)_6}]^{2 + }}\,,\,\,{[Cr{({H_2}O)_6}]^{2 + }}$
  • D
    ${[CoC{l_4}]^{2 - }}\,,\,{[Fe{({H_2}O)_6}]^{2 + }}$

Answer

Correct option: B.
$[Cr(H_2O)_6]^{2+} ,\,\,[Fe(H _2O)_6]^{2+}$
b
${[Cr{({H_2}O)_6}]^{2 + }}$ Here $Cr$ is in $Cr^{2+}$ form

In $[Fe(H_2O)]^{2+}$, $Fe$  is in $Fe^{2+}$ form. Both will have $4$ unpaired electrons.

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