$\mathrm{O}_{2}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \sigma 2 \mathrm{pz}^{2}\left(\pi 2 \mathrm{px}^{2}=\pi 2 \mathrm{py}^{2}\right)\left(\pi^{*} 2 \mathrm{px}^{1}=\pi^{*} 2 \mathrm{py}^{1}\right)$
$\mathrm{O}_{2}$ and $\mathrm{O}_{2}^{+}$ contain unpaired electron in $\pi^{*}$ ABMO so paramagnetic.
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$(1)$ An electron in an orbital of high angular momentum stays away from the nucleus than an electron in the orbital of lower angular momentum.
$(2)$ For a given value of the principal quantum number, the size of the orbit is inversely proportional to the azimuthal quantum number
$(3)$ According to wave mechanics, the ground state angular momentum is equal to $\frac {h}{2\pi }$
$(4)$ The plot of $\Psi \,\,Vs\,\,r$ for various azimuthal quantum numbers, shows peak shifting towards higher $r$ value