MCQ
The path difference between the two waves ${y_1} = {a_1}\sin \,\left( {\omega t - \frac{{2\pi x}}{\lambda }} \right)$ and ${y_2} = {a_2}\cos \,\left( {\omega t - \frac{{2\pi x}}{\lambda } + \phi } \right)$ is
- A$\frac{\lambda }{{2\pi }}\phi $
- ✓$\frac{\lambda }{{2\pi }}\left( {\phi + \frac{\pi }{2}} \right)$
- C$\frac{{2\pi }}{\lambda }\left( {\phi - \frac{\pi }{2}} \right)$
- D$\frac{{2\pi }}{\lambda }\phi $
