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The path difference between the two waves $y_1=a_1 \sin \left(\omega t-\frac{2 \pi x}{\lambda}\right)$ and $y_2=a_2 \cos \left(\omega t-\frac{2 \pi x}{\lambda}+\phi\right)$ is

• A
  $\frac{\lambda}{2 \pi} \phi$
• ✓
  $\frac{\lambda}{2 \pi}\left(\phi+\frac{\pi}{2}\right)$
• C
  $\frac{2 \pi}{\lambda}\left(\phi-\frac{\pi}{2}\right)$
• D
  $\frac{2 \pi}{\lambda} \phi$