MCQ
The path difference between the two waves $y_1=a_1 \sin \left(\omega t-\frac{2 \pi x}{\lambda}\right)$ and $y_2=a_2 \cos \left(\omega t-\frac{2 \pi x}{\lambda}+\phi\right)$ is ...........
- A$\frac{\lambda}{2 \pi} \phi$
- ✓$\frac{\lambda}{2 \pi}\left(\phi+\frac{\pi}{2}\right)$
- C$\frac{2 \pi}{\lambda}\left(\phi+\frac{\pi}{2}\right)$
- D$\frac{2 \pi}{\lambda} \phi$