The percentage error in measurement of mass and speed are $3\%$ and $2\%$ then error in kinetic energy will be .......... $\%$
A$6$
B$7$
C$10$
D$12$
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B$7$
b $E = \frac{1}{2}m{v^2}$
$\%%$ Error in $K.E$. $= \%$ error in mass $+ 2 × \%$ error in velocity $= 3 + 2 \times 2 = 7 \%$
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