MCQ
The $pH$ of the solution: $5\;mL$ of $\frac{M}{5}$,$HCl + 10\;mL$ of $\frac{M}{{10}}\;NaOH$ is
- A$5$
- B$3$
- ✓$7$
- D$8$
Milliequivalents of $NaOH$ $ = 10 \times \frac{1}{{10}} = 1$
$\therefore \;\;5ml\frac{M}{5}HCl = 10\,ml\frac{M}{5}HCl$
Hence the solution will be neutral i.e., $pH = 7$.
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