MCQ
The value of $K _{ C }$ is $64$ at $800\, K$ for the reaction $N _{2}( g )+3 H _{2}( g ) \rightleftharpoons 2 NH _{3}( g )$

The value of $K _{ C }$ for the following reaction is :

$NH_{3}(g) \rightleftharpoons \frac{1}{2} N _{2}(g)+\frac{3}{2} H_{2}(g)$

  • A
    $\frac{1}{4}$
  • $\frac{1}{8}$
  • C
    $8$
  • D
    $\frac{1}{64}$

Answer

Correct option: B.
$\frac{1}{8}$
b
$N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3} \rightarrow K _{ C }=64$

$2 NH _{3} \rightleftharpoons N _{2}+3 H _{2} \rightarrow K _{ C }=\frac{1}{64}$

$NH _{3} \rightleftharpoons \frac{1}{2} N _{2}+\frac{3}{2} H _{2} \rightarrow K _{ C }=\left(\frac{1}{64}\right)^{\frac{1}{2}}=\frac{1}{8}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free