[Given $pK _{ a }$ of $CH _{3} COOH =4.57$ ]
- A$3.57$
- B$4.57$
- C$2.57$
- ✓$5.57$
[Given $pK _{ a }$ of $CH _{3} COOH =4.57$ ]
Sodium acetate $\left( CH _{3} COONa \right)=0.10\, M$;
Acetic acid $\left( CH _{3} COOH \right)=0.01\, M$;
$pH$ of acidic buffer solution is given by
$pH = pK _{ a }+\log \frac{[\text { Salt }]}{[\text { Acid }]}$
$=4.57+\log \left(\frac{0.1}{0.01}\right)$
$=5.57$
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Given : $\Delta H _{ f }^{\ominus}\left( Al _2 O _3\right)=-1700\,kJ\,mol ^{-1}$
$\Delta H _{ f }^\theta\left( Fe _2 O _3\right)=-840\,kJ\,mol ^{-1}$
Molar mass of $Fe , Al$ and $O$ are $56,27$ and $16\,g\,mol ^{-1}$ respectively.


$\begin{array}{*{20}{c}} {N \equiv C} \\ {N \equiv C}\end{array}\,\,\left. {} \right\rangle C = C\,\left\langle {} \right.\,\begin{array}{*{20}{c}} {C \equiv N} \\ {C \equiv N} \end{array}$