- ✓One mole of $H{C_2}{H_3}{O_2}$ and $0.5$ mole of $NaOH$
- BOne mole of $N{H_4}Cl$ and one mole of $HCl$
- COne mole of $N{H_4}OH$ and one mole of $NaOH$
- DOne mole of $H{C_2}{H_3}{O_2}$ and one mole of $HCl$
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$\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})$
is $\mathrm{K}_{\mathrm{C}}=4.9 \times 10^{-2}$. The value of $\mathrm{K}_{\mathrm{C}}$ for the reaction given below is
$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ is
$(1)$ $Y$ is diamagnetic in nature while $Z$ is paramagnetic
$(2)$ Both $Y$ and $Z$ are coloured and have tetrahedral shape
$(3)$ In both $Y$ and $Z , \pi$-bonding occurs between $p$-orbitals of oxygen and $d$-orbitals of manganese.
$(4)$ In aqueous acidic solution, $Y$ undergoes disproportionation reaction to give $Z$ and $MnO _2$.