Area of the image of the house formed on the screen $=1.55 m ^{2}$

$=1.55 \times 10^{4} cm ^{2}$

Arial magnification, $m_{a}=\frac{\text { Area of image }}{\text { Area of object }}=\frac{1.55}{1.75} \times 10^{4}$

$\therefore$ Linear magnifications, $m_{l}=\sqrt{m_{\alpha}}$ $=\sqrt{\frac{1.55}{1.75} \times 10^{4}}=94.11$