MCQ
The photograph of a house occupies an area of $1.75\; cm^2$ on a $35\; mm$ slide. The slide is projected on to a screen, and the area of the house on the screen is $1.55\; m^2$. What is the linear magnification of the projector-screen arrangement
  • A
    $11.45$
  • $94.11$
  • C
    $52.36$
  • D
    $78.36$

Answer

Correct option: B.
$94.11$
b
Area of the house on the slide $=1.75 cm ^{2}$

Area of the image of the house formed on the screen $=1.55 m ^{2}$

$=1.55 \times 10^{4} cm ^{2}$

Arial magnification, $m_{a}=\frac{\text { Area of image }}{\text { Area of object }}=\frac{1.55}{1.75} \times 10^{4}$

$\therefore$ Linear magnifications, $m_{l}=\sqrt{m_{\alpha}}$ $=\sqrt{\frac{1.55}{1.75} \times 10^{4}}=94.11$

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