MCQ
The plot of $\log\,K$ Vs $\frac{1}{T}$ helps to calculate
- AThe energy of activation
- BThe rate constant of the reaction
- CThe order of reaction
- ✓The energy of activation as well as frequency factor
$\log k=\log A-\frac{E_a}{2.303} \cdot \frac{1}{T}$
Plot of $\log k\,vs\, \frac{1}{ T }$ is a straight line.
Slope $=-\frac{ E _{ a }}{2.303 R }$
Intercept $=\log A$
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