MCQ
The points (3, 2, 0), (5, 3, 2) and (-9, 6, -3), are the vertices of a triangle ABC.AD is the internal bisector of $\angle\text{BAC}$ which meets BC at D. Then the co-ordinates of D, are:
- A$\Big[\frac{17}{16},\frac{57}{16},\frac{19}{8}\Big]$
- ✓$\Big[\frac{19}{8},\frac{57}{16},\frac{17}{16}\Big]$
- C$\Big[0,0,\frac{17}{16}\Big]$
- D$\Big[\frac{17}{16},0,0\Big]$