MCQ
The points (3, 2, 0), (5, 3, 2) and (-9, 6, -3), are the vertices of a triangle ABC.AD is the internal bisector of $\angle\text{BAC}$ which meets BC at D. Then the co-ordinates of D, are:
  • A
    $\Big[\frac{17}{16},\frac{57}{16},\frac{19}{8}\Big]$
  • $\Big[\frac{19}{8},\frac{57}{16},\frac{17}{16}\Big]$
  • C
    $\Big[0,0,\frac{17}{16}\Big]$
  • D
    $\Big[\frac{17}{16},0,0\Big]$

Answer

Correct option: B.
$\Big[\frac{19}{8},\frac{57}{16},\frac{17}{16}\Big]$
  1. $\Big[\frac{19}{8},\frac{57}{16},\frac{17}{16}\Big]$

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