MCQ
The points which trisect the line segment joining the points $(0, 0)$ and $(9, 12)$ are
- ✓$(3,4),\, (6,8)$
- B$(4,3),\, (6,8)$
- C$(4,3),\, (8,6)$
- D$(3,4),\, (8,6)$
$(i)$ Point $B \,(x, y)$ divides $AD$ in $1 : 2$
$\therefore \,\,\,\,x = \frac{{0 + 9}}{3} = 3$ and $y = \frac{{0 + 12}}{3} = 4$
$(ii)$ Now point $C \,(x, y)$ divides $AD$ in $2 : 1$,
Then $x = \frac{{0 + 18}}{3} = 6$ and $y = \frac{{0 + 24}}{3} = 8$.
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