MCQ
The polar molecule among the following is
- A$CC{l_4}$
- B$C{O_2}$
- ✓$C{H_2}C{l_2}$
- D$C{H_2} = C{H_2}$
✓
Answer
Correct option: C.
$C{H_2}C{l_2}$
c
$CH _2 Cl _2$ is a polar molecule. The molecule is tetrahedral due to $4$ electron repulsion around the central $C$ atom. Although the bond arrangement around the $C$ atom in $CH _2 Cl _2$ is symmetrical, the differing polarities of the $C - H$ and $C - Cl$ bonds means the effect of the polar bonds is not cancelled, so the molecule is polar.
$CH _2 Cl _2$ is a polar molecule. The molecule is tetrahedral due to $4$ electron repulsion around the central $C$ atom. Although the bond arrangement around the $C$ atom in $CH _2 Cl _2$ is symmetrical, the differing polarities of the $C - H$ and $C - Cl$ bonds means the effect of the polar bonds is not cancelled, so the molecule is polar.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is correct representation of the reaction when $BF_3$ reacts with ammonia ?
→The values of $K_p/K_c$ for the following reactions at $300\, K$ are respectively (At $300\, K, RT = 24.62\, dm^3\, atm \,mol^{-1}$)
→${N_2}(g) + {O_2}(g) \rightleftharpoons 2NO(g)$
${N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g)$
${N_2}(g) + 3{H_2}(g) \rightleftharpoons 2N{H_3}(g)$
The mass number of an anion, ${X^{3 - }}$, is $14.$ If there are ten electrons in the anion, the number of neutrons in the nucleus of atom, ${X_2}$ of the element will be
→The oxidation state of the most electronegative element in the products of the reaction between $\mathrm{BaO}_2$ and $\mathrm{H}_2 \mathrm{SO}_4$ are :
→Which reaction is $NOT$ a redox reaction?
→Resonance hybrid of nitrate ion is
Circle represent most acidic hydrogens in these molecules. Which of the following is correct representation ?
Which of the following is an electrophile
The ratio of lone pair and bond pair electrons on central $\ce{I}$ atom in $\text{I}_3^−$ :
→According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as $(h = 6.62 \times 10^{-27} \ ergs,$$ \ c = 3 \times cm s^{-1}, $$\ N_A = 6.02 \times 10^{-23} \ mol^{-1})$
→