MCQ
The possible quantum number for $3d$ electron are
- A$\ce{n=3, l=1, m_1=+1, m_s=-\frac{1}{2}}$
- ✓$\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=+2, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$
- C$\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}_{\mathrm{l}}=-1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$
- D$\mathrm{n}=3, \mathrm{l}=0, \quad \mathrm{~m}_{\mathrm{l}}=+1, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$