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Electron, Photon, Photo-electric Effect and X-Rays — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsElectron, Photon, Photo-electric Effect and X-Rays1 Mark
MCQ
The potential difference between the cathode and the target in a Collidge tube is $100\  \mathrm{kV}$. The minimum wavelength of the X-rays emitted by the tube is
  • A
    $0.66 \mathring A$
  • B
    $9.38 \mathring A$
  • C
    $0.246 \mathring A$
  • ✓
    $0.123 \mathring A$
✓

Answer

Correct option: D.
$0.123 \mathring A$
$\lambda_{\min }=\frac{h c}{e V}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19} \times 100 \times 10^3}=0.123 \mathring A$

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