The pressure of a medium is changed from $1.01 × 10^5$ $Pa$ to $1.165 × 10^5$ $Pa$ and change in volume is $10\% $ keeping temperature constant. The Bulk modulus of the medium is
Medium
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(d) $K = \frac{{\Delta p}}{{\Delta V/V}}$$ = \frac{{(1.165 - 1.01) \times {{10}^5}}}{{10/100}} = \frac{{0.155 \times {{10}^5}}}{{1/10}}$
$ = 1.55 \times {10^5}pa$
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