The probability distribution of a discrete random variable X is given below:
$\text{X}:$
$2$
$3$
$4$
$5$
$\text{P}(\text{X}):$
$\frac{5}{\text{k}}$
$\frac{7}{\text{k}}$
$\frac{9}{\text{k}}$
$\frac{11}{\text{k}}$
The value of k is:
A
8
B
16
C
32
D
48
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C
32
$\sum\limits_2^5\text{P}(\text{x})=1$
$\frac{5}{\text{k}}+\frac{7}{\text{k}}+\frac{9}{\text{k}}+\frac{11}{\text{k}}=1$
$\text{k}=32$ NOTE: Question is modified.
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