Question
The probability distribution of a discrete random variable X is given below:

$\text{X}:$

$2$

$3$

$4$

$5$

$\text{P}(\text{X}):$

$\frac{5}{\text{k}}$

$\frac{7}{\text{k}}$

$\frac{9}{\text{k}}$

$\frac{11}{\text{k}}$

The value of k is:

  1. 8
  2. 16
  3. 32
  4. 48

Answer

  1. 32

Solution:

$\sum\limits_2^5\text{P}(\text{x})=1$

$\frac{5}{\text{k}}+\frac{7}{\text{k}}+\frac{9}{\text{k}}+\frac{11}{\text{k}}=1$

$\text{k}=32$

NOTE: Question is modified.

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