MCQ
The probability of throwing a number greater than $2$ with a fair die is :
- A$\frac{2}{5}$
- B$\frac{5}{6}$
- C$\frac{1}{3}$
- ✓$\frac{2}{3}$
✓
Answer
Correct option: D.
$\frac{2}{3}$
The numbers on a fair die are $\{1, 2, 3, 4, 5\}$ and $6.$
So, there are $6$ numbers in total.
The number greater than $2$ are $3, 4, 5$ and $6.$
So, there are $4$ numbers.
$P($getting a number greater than $2)$
$=\frac{4}{6}$
$=\frac{2}{3}$
So, there are $6$ numbers in total.
The number greater than $2$ are $3, 4, 5$ and $6.$
So, there are $4$ numbers.
$P($getting a number greater than $2)$
$=\frac{4}{6}$
$=\frac{2}{3}$
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