The probability that a leap year will have $53$ sundays is:
A$\frac17$
B$\frac27$
C$\frac57$
D$\frac67$
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B$\frac27$
A leap year has $52$ weeks and $2$ days.
The $53^{rd}$ Sunday will be from these extra two days
These $2$ days can be $($Sunday, Monday$)$ or $($Mon, Tue$)$ or $($Tue, Wed$).....$(Sat, Sun$)$
There are $7$ possibilities for these $2$ days
Out of which Sunday is coming in $2$ possibilities.
$\therefore P(2$ sundays in leap year$) =\frac27$
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