The probability that an automobile will be stolen and found within one week is 0.0006. The probability that an automobile will be stolen is 0.0015. The probability that a stolen automobile will be found in one week is:
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionChoose the correct answer from the given four options.The probability that exactly two of the three balls were red, the first ball being red, is:
- 2View SolutionA four-digit number is formed by using the digits 1, 2, 4, 8 and 9 without repitition. If one number is selected from those numbers, then what is the probability that it will be an odd number?
- 3View SolutionThe least number of times a fair coin must be tossed so that the probability of getting at least one head is at least 0.8, is:
- 4If $\text{P(B)}=\frac{3}{5},\text{P}(\text{A}|\text{B})=\frac{1}{2}$ and $\text{P}(\text{A}\cup\text{B})=\frac{4}{5},$ then $\text{P}(\text{B}|\overline{\text{A}})=$View Solution
- 5The probability that a leap year will have $53$ sundays is:View Solution
- 6Choose the correct answer from the given four options.View Solution
If $\text{P}(\text{A})=\frac{3}{10},\text{P}(\text{B})=\frac{2}{5}$ and $\text{P}(\text{A}\cup\text{B})=\frac{3}{5},$ then $\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)+\text{P}\Big(\frac{\text{A}}{\text{B}}\Big)$ equas: - 7Fifteen coupons are numbered $1$ to $15$. Seven coupons are selected at random one at a time with replacement. The probability that the largest number appearing on a selected coupon is $9$ is:View Solution
- 8A biased coin with probabilty p, 0 < p < 1, of heads is tossed until a head appears for the first time. If the probability that the number of tosses required is even is $\frac{2}{5},$ then p equals:View Solution
- 9If $\text{P(A)}=\frac{7}{13},\text{P(B)}=\frac{9}{13}$ and $\text{P}(\text{A}\cap\text{B})=\frac{4}{13}.$ then, $\text{P}(\overline{\text{A}}|\text{B})=$View Solution
- 10View SolutionThe probability that a leap year will have 53 fridays or 53 Saturdays is.