MCQ
The probability that a leap year will have $53$ Sundays or $53$ Mondays is :
  • A
    $\frac{2}{7}$
  • B
    $\frac{4}{7}$
  • C
    $\frac{1}{7}$
  • $\frac{3}{7}$

Answer

Correct option: D.
$\frac{3}{7}$
Leap year contains $366$ days $= 52$ weeks $+\ 2$ days
$52$ weeks contain $52 $ Sundays and $52$ weeks contain $52$ Mondays
We will get $53$ Sundays or $53$ Mondays if one of the remaining two days is a Sunday or Monday,
Total possibilities for two days are :
$\text{(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday)} $
$\text{(Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)}$
Number of Total possible outcomes $= 7$
Number of possible outcomes either Sunday or Monday or Both $= 3$
Required Probability $=\frac{3}{7}$

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