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Probability — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsProbability1 Mark
MCQ
The probability that a non $-$ leap year has $53$ Sundays, is :
  • A
    $\frac{2}{7}$
  • B
    $\frac{5}{7}$
  • C
    $\frac{6}{7}$
  • ✓
    $\frac{1}{7}$
✓

Answer

Correct option: D.
$\frac{1}{7}$
In a non leap years, number of days $= 365$ i.e. $52$ weeks $+\ 1$ day
$\therefore$ Probability of being $53$ Sundays
$=\frac{\text{m}}{\text{n}}=\frac{1}{\text{No. of day in a week}}=\frac{1}{7}$

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