MCQ
The product obtained when silica reacts with hydrogen fluoride is
- A$SiF_4$
- ✓$H_2SiF_6$
- C$H_2SiF_4$
- D$H_2SiF_3$
The reactions are as follows:
$\mathrm{SiO}_{2}+4 \mathrm{HF} \rightarrow \mathrm{SiF}_{4}+2 \mathrm{H}_{2} \mathrm{O}$
$3 \mathrm{SiF}_{4}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{2} \mathrm{SiF}_{6}+\mathrm{H}_{4} \mathrm{SiO}_{4}$
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$AB , A _2$ and $B _2$ are diatomic molecule. If the bond enthalpies of $A _2, B _2$ and $AB$ are in the ratio $1: 0.5: 1$, then the bond enthalpy of $A_2$ is $......\,kJ\,mol ^{-1}$ (Nearest integer)
$\text{Zn}+2\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ }\text{ZnCl}_2+\text{H}_2$