MCQ
The quantum number of four electrons are given below
$I. n = 4,l = 2,m_l = -2, m_s = -1/ 2$
$II. n = 3,l = 2, m_l = 1,m_s = +1/ 2$
$III. n = 4,l = 1, m_l = 0, m_s = +1/ 2$
$IV. n = 3,l = 1, m_l = 1; m_s = -1/ 2$
The correct order of their increasing energies will be
- A$I < III < II < IV$
- B$I < II < III < IV$
- ✓$IV < II < III < I$
- D$IV < III < II < I$