MCQ
If $5$ moles of $BaCl _2$ is mixed with $2$ moles of $Na _3 PO _4$, the maximum number of moles of $Ba _3\left( PO _4\right)_2$ formed is $............$(Nearest integer)
- A$2$
- B$3$
- C$4$
- ✓$1$
✓
Answer
Correct option: D.
$1$
d
$3 BaCl _2+2 Na _3 PO _4 \rightarrow Ba _3\left( PO _4\right)_2+6 NaCl$
$3 BaCl _2+2 Na _3 PO _4 \rightarrow Ba _3\left( PO _4\right)_2+6 NaCl$
$Na _3 PO _4$ is limiting reagent.
$2$ mole $Na _3 PO _4$ gives $1$ mole of $Ba _3\left( PO _4\right)_2$
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