MCQ
The range of a projectile for a given initial velocity is maximum when the angle of projection is ${45^o}$. The range will be minimum, if the angle of projection is ......... $^o$
- ✓$90$
- B$180$
- C$60$
- D$75$
✓
Answer
Correct option: A.
$90$
a
(a)Range$ = \frac{{{u^2}\sin 2\theta }}{g}$; when $\theta = 90^\circ $, $R = 0$ i.e. the body will fall at the point of projection after completing one dimensional motion under gravity.
(a)Range$ = \frac{{{u^2}\sin 2\theta }}{g}$; when $\theta = 90^\circ $, $R = 0$ i.e. the body will fall at the point of projection after completing one dimensional motion under gravity.
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