MCQ
The range of a projectile for a given initial velocity is maximum when the angle of projection is $45^{\circ}$. The range will be minimum, if the angle of projection is
- ✓$90^{\circ}$
- B$180^{\circ}$
- C$60^{\circ}$
- D$75^{\circ}$
✓
Answer
Correct option: A.
$90^{\circ}$
Range $=\frac{ u ^2 \sin 2 \theta}{g}$, when $\theta=90^{\circ}, R=0$ i.e. the body will fall at the point of projection after completing one dimensional motion under gravity.
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