MCQ
The range of the function f(x) = 3x - 2‚ is.
- A$(-\infty,\infty)$
- B$\text{R}-(3)$
- C$(-\infty,0)$
- D$(0,- \infty)$
Solution:
Let the given function is
y = 3x - 2
⇒ y + 2 = 3x
$\Rightarrow \text{x} =\frac{(\text{y}+2)}{3}$
Now x is satisfied by all values.
So, Range {f(x)} = R $=(-\infty,\infty)$
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