- ✓$1 :\, -1$
- B$1 : 1$
- C$1 : 2$
- D$2 : 1$
$- T . E .= K. E .=- P . E. / 2$
Ratio $K.E : T.E :: 1:-1$
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$(I){\mkern 1mu} C{H_3}CH_2^ - {\mkern 1mu} + {\mkern 1mu} \mathop {C{H_3}N{H_2}}\limits_{p{K_a} = 35} \rightleftharpoons \mathop {C{H_3}C{H_3}}\limits_{p{K_a} = 50} + C{H_3}N{H^ - }$
$(II){\mkern 1mu} {F^ - }{\mkern 1mu} + {\mkern 1mu} \mathop {{H_2}O}\limits_{p{K_a} = 15.7} \rightleftharpoons \mathop {HF}\limits_{p{K_a} = 3.2} + H{O^ - }$
$\mathrm{NaCl}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{Conc} .) \rightarrow(\mathrm{A})+$ Side products
$(\mathrm{A})+\mathrm{NaOH} \rightarrow(\mathrm{B})+$ side product
$(\mathrm{B})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{dilute})+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow(\mathrm{C})+$ Side product
The sum of the total number of atoms in one molecule each of $(A), (B)$ and $(C)$ is
