The reaction C H_3 CH = C H_2 (CO + H_2 ) _ H^ ^ + C H_3 - CH - C… - Vidyadip

MCQ

The reaction $C{H_3}CH = C{H_2}\mathop {\xrightarrow{{(CO + {H_2})}}}\limits_{{H^{^ + }}} C{H_3} - \mathop {\mathop {CH - C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \,\,\,\,\,}\limits_{COOH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \,\,$is known as

A
Wurtz reaction
✓
Koch reaction
C
Clemmensen reduction
D
Kolbe’s reaction

✓

Answer

Correct option: B.

Koch reaction

b
(b) Koch reaction : (Carboxylation of Alkene)

$C{H_3} - CH = C{H_2}\mathop {\xrightarrow{{{\text{Water gas (}}CO + {H_2})}}}\limits_{{{400}\,^o}C,{\kern 1pt} {H_3}P{O_4}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,COOH} \\
{|\,\,\,\,} \\
{C{H_3} - CH - C{H_3}}
\end{array}}\limits_{Isobutyric\,acid} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The major product in the following reaction is

Which of the following pair represent pair of diastereomers ?

Oxidation of $NO$ in air produces

For the reaction, $2Fe(NO_3)_3 + 3Na_2CO_3 \to Fe_2(CO_3)_3 + 6NaNO_3$ Initially if $2.5$ mole of $Fe(NO_3)_3$ and $3.6$ mole of $Na_2CO_3$ is taken. If $6.3$ mole of $NaNO_3$ is obtained then $\%$ yield of given reaction is :-

$\mathop {Salt\,\,'A'}\limits_{(Colourless)} \,\,\xrightarrow{{Cu}}$ Blue solution

$\mathop {Salt\,\,'A'}\limits_{(Colourless)} \,\,\xrightarrow[{(aq)}]{{HCl}}$ White ppt

$\mathop {Salt\,\,'A'}\limits_{(Colourless)} \,\,\xrightarrow[{{H_2}S{O_4}}]{{Conc.}}$ Brown fumes

Ethylene react with $Br_2$ give $1,2-$ Dibromoethane intermediate of reaction is

The main product of following reaction will be

The name of complex ion, $[Fe(CN)_6]^{3-}$ is

In $C{H_3}C{H_2}OH\mathop {\xrightarrow{X}}\limits_{{{350}\,^o}C} C{H_2} = C{H_2} + {H_2}O;$ $'X' $ is

$X$ can be prepared by except