MCQ
The reaction of $HBr$ with $\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C = C{H_2}}
\end{array}$ in the presence of peroxide will give
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C = C{H_2}}
\end{array}$ in the presence of peroxide will give
- A$\begin{array}{*{20}{c}}
{C{H_3}CBrC{H_3}} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,}
\end{array}$ - B$CH_3$ $CH_2$ $CH_2$ $CH_2$ $Br$
- ✓$\begin{array}{*{20}{c}}
{\,\,C{H_{3\,\,\,\,\,\,\,}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}CHC{H_2}Br}
\end{array}$ - D$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,|} \\
{C{H_3}C{H_2}CHC{H_3}}
\end{array}$
