MCQ
The reaction of Lucas reagent is fast with
- ✓${\left( {C{H_3}} \right)_3}COH$
- B${(C{H_3})_2}CHOH$
- C$C{H_3}{(C{H_2})_2}OH$
- D$C{H_3}C{H_2}OH$
In this reaction, carbocation is formed as an intermediate and thus the stability and ease of carbocation formation determine the rate of the reaction as that's the slow step of the mechanism.
Hence the order of reactivity is tertiary alcohol $ > $ secondary alcohol $ > $ primary alcohol by $SN ^1$ mechanism.
Thus $C \left( CH _3\right)_3 OH$ being tertiary alcohol will react most readily with Lucas reagent.
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Statement $I$: Aniline reacts with con. $\mathrm{H}_2 \mathrm{SO}_4$ followed by heating at $453-473 \mathrm{~K}$ gives $\mathrm{p}$ aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement $II$: In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the $\mathrm{AlCl}_3$ catalyst. Due to this, nitrogen of aniline aquires a positive charge and acts as deactivating group.
In the light of the above statements, choose the correct answer from the options given below :