MCQ
The reaction of propene with HOCl(Cl2 + H2O) proceeds through intermediate:
  • A
    $\ \ \ \ \ \ \ \ \ \ \ \ \oplus\\\text{CH}_3-\text{C}\text{H}-\text{CH}_2\text{OH}$
  • B
    $\ \ \ \ \ \ \ \ \ \ \ \ \oplus\\\text{CH}_3-\text{C}\text{H}-\text{CH}_2-\text{Cl}$
  • C
    $ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \oplus\\ \text{CH}_3-\text{CH(OH)}\text{CH}_2$
  • D
    $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \oplus\\ \text{CH}_3\text{CHCl }\text{CH}_2$

Answer

  1. $\ \ \ \ \ \ \ \ \ \ \ \ \oplus\\\text{CH}_3-\text{C}\text{H}-\text{CH}_2-\text{Cl}$

Explanation:

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ominus\\\text{HOCl}\rightarrow\text{OCH}+\text{Cl}^+$

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