MCQ
The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of
- A$PbCl _2$
- B$PbCl _4$
- ✓$\left[ PbCl _4\right]^{2-}$
- D$\left[ PbCl _6\right]^{2-}$
