The reading of the ammeter in the adjoining figure will be .............. $A$
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In the given circuit, the resistances $6\, \Omega, 3\, \Omega$ and $2\, \Omega$ are connected in parallel. their effective resistance will be.
$\frac{1}{R_{p}}=\frac{1}{6}+\frac{1}{3}+\frac{1}{2}=\frac{1+2+3}{6}=\frac{6}{6}$
or $\mathrm{R}_{\mathrm{p}}=1\, \Omega$
the equivalent circuit is as shown in the figure.
Current in the circuit, $\mathrm{I}=\frac{2}{5}=0.4 \mathrm{\,A}$
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