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The circuit shown here is used to compare the emf of two cells $E_1$ and $E_2 (E_1 > E_2)$. The null point is at $C$ when the galvanometer is connected to $E_1$. When the galvanometer is connected to $E_2$, the null point will be
  • Ato the left of $C$
  • Bto the right of $C$
  • Cat $C$ itself
  • D
    no change in null point
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