$Ph - C \equiv C - Ph \to $ 
- ACat. Hydrogenation
- B$H_2/$ Lindlar Cat.
- ✓$Li/NH_3$
- D$LiAlH_4$
$Ph - C \equiv C - Ph \to $ 
$Ph-C\equiv C-Ph\xrightarrow[Brich\,reduction]{Li\,in\,liq.N{{H}_{3}}}\begin{matrix}
^{Ph} \\
_{H} \\
\end{matrix}\begin{matrix}
\text{ }\!\!\backslash\!\!\text{ } \\
/ \\
\end{matrix}C=C\begin{matrix}
/ \\
\text{ }\!\!\backslash\!\!\text{ } \\
\end{matrix}_{Ph}^{H}$
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$\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_2}Cl}\limits_1 $ $\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_3}}\limits_2 $ $\mathop {\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C\mathop C\limits^ + {{(C{H_3})}_2}} \\
{|\,\,\,\,} \\
{Cl\,\,\,}
\end{array}}\limits_3 $ $\mathop {{{(C{H_3})}_2}\mathop C\limits^ + CH{{(C{H_3})}_2}}\limits_4 $
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Choose the correct option($s$).
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