MCQ
The reagent needed for converting
$Ph - C \equiv C - Ph \to $ 
- ACat. Hydrogenation
- B$H_2/$ Lindlar Cat.
- ✓$Li/NH_3$
- D$LiAlH_4$
$Ph - C \equiv C - Ph \to $
$Ph-C\equiv C-Ph\xrightarrow[Brich\,reduction]{Li\,in\,liq.N{{H}_{3}}}\begin{matrix}
^{Ph} \\
_{H} \\
\end{matrix}\begin{matrix}
\text{ }\!\!\backslash\!\!\text{ } \\
/ \\
\end{matrix}C=C\begin{matrix}
/ \\
\text{ }\!\!\backslash\!\!\text{ } \\
\end{matrix}_{Ph}^{H}$
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${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(g)$ is $\Delta {H_1}$ and that of
${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(l)$ is $\Delta {H_2}$. Then
| Condition | Temperature |
| $(1)$ Spontaneous | $(p)$ $273\,K$ |
| $(2)$ At equilibrium | $(q)$ $260\, K$ |
| $(3)$ Non-spontaneous | $(r)$ $280\, K$ |