MCQ
The reagent used for converting ethanoic acid to ethanol is
- ✓$LiAl{H_4}$
- B$KMn{O_4}$
- C$PC{l_3}$
- D${K_2}C{r_2}{O_7}/{H^ + }$
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$\left[\mathrm{TeBr}_6\right]^{2-},\left[\mathrm{BrF}_2\right]^{+}, \mathrm{SNF}_3 \text {, and }\left[\mathrm{XeF}_3\right]^{-}$ (Atomic numbers : $\mathrm{N}=7, \mathrm{~F}=9, \mathrm{~S}=16, \mathrm{Br}=35, \mathrm{Te}=52, \mathrm{Xe}=54$ )