MCQ
The reduction potential of hydrogen half-cell will be negative if :
- A$p(H_2) = 1\,atm$ and $[H^+] = 2.0\,M$
- B$p(H_2) = 1\,atm$ and $[H^+] = 1.0\,M$
- ✓$p(H_2) = 2\,atm$ and $[H^+] = 1.0\,M$
- D$p(H_2) = 2\,atm$ and $[H^+] = 2.0\,M$
$E=E^{\circ}-\frac{0.059}{1} \log \frac{P_{H_{2}}^{1 / 2}}{\left|H^{+1}\right|}$
Now if $P_{H_{2}}=2$ atm and $\left[H^{+}\right]=1 M$
then $E=0-\frac{0.059}{1} \log \frac{2^{1 / 2}}{1}=-2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$
$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$

