MCQ
The relation between change in internal energy $(\Delta E)$, change in enthalpy $(\Delta H)$ and work done $ (W)$ is represented as
- ✓$\Delta H = \Delta E + W$
- B$W = \Delta E - \Delta H$
- C$\Delta E = W - \Delta H$
- D$\Delta E = \Delta H + W$
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$NO _{3}^{-}, H _{2} O _{2}, BF _{3}, PCl _{3}, XeF _{4},SF _{4}, XeO _{3}, PH _{4}^{+}, SO _{3},\left[ Al ( OH )_{4}\right]^{-}$
$HI \rightleftharpoons \frac {1}{2} H_{2(g)} + \frac{1}{2} I_{2(g)}$
is $8.0$. The equilibrium constant of the reaction
$H_{2( g )} + I_{2(g)} \rightleftharpoons 2HI_{ ( g )}$ will be