MCQ
The relation between time and displacement for two particles is given by
$y_1=0.06 \sin 2 \pi\left(0.04 t+\phi_1\right), y_2=0.03 \sin 2 \pi\left(1.04 t+\phi_2\right)$
The ratio of the intensity of the waves produced by the vibrations of the two particles will be
$y_1=0.06 \sin 2 \pi\left(0.04 t+\phi_1\right), y_2=0.03 \sin 2 \pi\left(1.04 t+\phi_2\right)$
The ratio of the intensity of the waves produced by the vibrations of the two particles will be
- A$2: 1$
- B$1: 2$
- ✓$4: 1$
- D$1: 4$
