MCQ
The relation between voltage sensitivity (${\sigma _V}$) and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)
  • $\frac{{{\sigma _i}}}{G} = {\sigma _V}$
  • B
    $\frac{{{\sigma _{_V}}}}{G} = {\sigma _i}$
  • C
    $\frac{G}{{{\sigma _V}}} = {\sigma _i}$
  • D
    $\frac{G}{{{\sigma _i}}} = {\sigma _V}$

Answer

Correct option: A.
$\frac{{{\sigma _i}}}{G} = {\sigma _V}$
a
(a) ${\sigma _i} = \frac{\theta }{i} = \frac{\theta }{{iG}} \cdot G = {\sigma _{_V}}G$ $==>$ $\frac{{{\sigma _i}}}{G} = {\sigma _V}$

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