MCQ
The relationship between standard reduction potential of cell and equilibrium constant is shown by
  • A
    $E_{cell}^0 = \frac{n}{{0.059}}\log {K_c}$
  • $E_{cell}^0 = \frac{{0.059}}{n}\log {K_c}$
  • C
    $E_{cell}^0 = 0.059\,n\,\log {K_c}$
  • D
    $E_{cell}^0 = \frac{{\log {K_c}}}{n}$

Answer

Correct option: B.
$E_{cell}^0 = \frac{{0.059}}{n}\log {K_c}$
b
(b)$E_{{\rm{cell}}}^o = \frac{{2.303\,\,RT}}{{nF}}\log \,K = \frac{{0.0591}}{n}\log \,{K_c}\,at\,\,298\,K$.

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