Question
The separation between a node and the next antinode in a vibrating air column is 25cm. If the speed of sound in air is 340m/s, find the frequency of vibration of the air column.
✓
Answer
$\text{v}=340\text{m/s}$Distances between two nodes or antinodes
$\Rightarrow\frac{\lambda}{4}=25\text{cm}$
$\Rightarrow\lambda=100\text{cm}=1\text{m}$
$\Rightarrow\text{n}=\frac{\text{v}}{\lambda}=340\text{Hz}.$
$\Rightarrow\frac{\lambda}{4}=25\text{cm}$
$\Rightarrow\lambda=100\text{cm}=1\text{m}$
$\Rightarrow\text{n}=\frac{\text{v}}{\lambda}=340\text{Hz}.$
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